Q. The units J $Pa^{- 1}$ is equivalent to
A) $m^{3}$
B) $cm^{3}$
C) $dm^{3}$
D) None of these
Explanation
(a)
$JPa^{- 1} = \frac{J}{Pa}$
$= \frac{work}{pressure} = \frac{N - m}{N/m^{2}}$
$= m^{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.