Q. 1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is
A) 1.520
B) 0.995
C) 19.00
D) 9.00
Explanation
(d)
$\frac{Wt.of\ metal\ hydroxide}{Wt.of\ metal\ oxide}$
$= \frac{Eq.wt.of\ metal + Eq.wt.of\ OH^{-}}{Eq.wt.of\ metal + Eq.wt.of\ O_{2}^{2 -}}$
$\Longrightarrow \frac{1.520}{0.995} = \frac{E + 17}{E + 8}$
On solving, $E = 9.0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.