Q. If the density of water is 1 g $cm^{- 3}$ then the volume occupied by one molecule of water is approximately
A) 18 $cm^{3}$
B) 22400 $cm^{3}$
C) $6.02 \times 10^{- 23}cm^{3}$
D) $3.0 \times 10^{- 23}cm^{3}$
Explanation
(d)
Mass of one molecule of water
$= \frac{mol.mass}{N_{0}} = \frac{18}{6.02 \times 10^{23}}g$
$\therefore$ Volume of 1 molecule of water $= \frac{mass}{density}$
$= \frac{18 \times 10^{- 23}}{6.02 \times 1}$
$= 3 \times 10^{- 23}$ mL
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.