Explanation

(c)
Atoms in 2.0 mol of
$S_{8} = 2 \times 8 \times 6.02 \times 10^{23}$
$= 9.632 \times 10^{24}$
2. Atoms in 6.0 mol of S=$6 \times 6.02 \times 10^{23}$
$= 3.612 \times 10^{24}$
Atoms in 5.5 mol of
$SO_{2} = 3 \times 5.5 \times 6.02 \times 10^{23} = 9.93 \times 10^{24}$
Atoms in 4.48 L of $CO_{2}$ at STP=$\frac{3 \times 4.48 \times 6.02 \times 10^{23}}{22.4}$
$= 3.612 \times 10^{23}$