Q. The mass of 112 $cm^{3}$ of $CH_{4}$ gas a STP is
A) 0.16 g
B) 0.8 g
C) 0.08 g
D) 1.6 g
Explanation
(c)
$\because$ Mass of 22400 $cm^{3}\ \ CH_{4} = 16g$
$\therefore$ Mass of 112 $cm^{3}CH_{4} = \frac{16 \times 112}{22400} = 0.08g$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.