Q. An organic compound contains 20.0% C, 6.66% H, 47.33% N and the rest was oxygen. Its molar mass is 60 g $mol^{- 1}$ the molecular formula of the compound is
A) $CH_{4}N_{2}O$
B) $C_{2}H_{4}NO_{2}$
C) $CH_{3}N_{2}O$
D) $CH_{4}N_{2}O_{2}$
Explanation
(a)
Ratio of atoms
$C:H:N:O :: \frac{20.0}{12}:\frac{6.66}{1}:\frac{47.33}{14}:\frac{26.01}{16}$
$= 1.67:6.66:3.38:1.63$
$= 1:4:2:1$
Empirical formula = $CH_{4}N_{2}O$
Molar empirical formula mass $= 60$g
Molecular formula $= CH_{4}N_{2}O$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.