Q. An organic compound containing C and H has 92.3% of carbon, its empirical formula is
A) CH
B) ${CH}_{3}$
C) ${CH}_{2}$
D) ${CH}_{4}$
Explanation
(a)
[table] Element | %ntage atomic wt. | Simplest ratio ; C
H | $\frac{92.3}{12} = 7.69$
$\frac{7.7}{1} = 7.70$ | $\frac{7.69}{7.69} = 1$
$\frac{7.70}{7.69} = 1$ [/table]
$\therefore$ Empirical formula=CH
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.