Q. If $H_{2}SO_{4}$ ionises as $H_{2}SO_{4} + 2H_{2}O \rightarrow 2H_{3}O^{+} + SO_{4}^{2}$, then total number of ions produced by 0.1 M $H_{2}SO_{4}$ will be
A) $9.03 \times 10^{21}$
B) $3.01 \times 10^{22}$
C) $6.02 \times 10^{22}$
D) 1.8$\times 10^{23}$
Explanation
(d)
1 mole of $H_{2}SO_{4}$ gives = 3 moles of ions or $3 \times 6.023 \times 10^{23}$ ions
$\therefore 0.1$ mole of $H_{2}SO_{4}$ will give $= 0.1 \times 3 \times 6.023 \times 10^{23}$ ions
$= 1.8 \times 10^{23}$ ions
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.