Q. A student performs a titration with different burettes and finds titre values of 25.2 mL, 25.25 mL, and 25.0mL. The number of significant figures in the average titre value is
A) 1
B) 2
C) 3
D) 4
Explanation
(c)
$Average\ value = \frac{25.2 + 25.25 + 25.0}{1} = \frac{75.45}{3}$
= 25.15 = 25.2 mL
Number of significant figure is 3.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.