Q. 1 L oxygen gas at STP will weigh
A) $1.43_{\ g}$
B) ${2.24}_{\ g}$
C) ${11.2\ }_{g}$
D) ${22.4}_{\ g}$
Explanation
(a)
Given, volume of $O_{2} = 1L\$
$\because 22.4\ L\ of\ O_{2}\ at\ STP = 32\ g\$
$\therefore$ $1\ L\ of\ O_{2}\ at\ STP = \frac{32}{22.4}g\$
= 1.43 g
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.