Q. What is the equivalent weight of ${SnCl}_{2}$ in the following reaction, ${SnCl}_{2} + \ {Cl}_{2} \rightarrow {SnCl}_{4}$?
A) 95
B) 45
C) 60
D) 30
Explanation
(a)
$SnCl_{2} + Cl_{2} \rightarrow SnCl_{4}$
190 71
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{190}{E_{1}} = \frac{71}{35.5}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E_{1} = 95$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.