(b) $4.6 \times 10^{22}$ atoms weight =13.8 g Hence, $6.02 \times 10^{23}$ atoms will weigh $= \ \underset{4.6 \times 10^{22}}{\overset{13.8 \times 6.02 \times 10^{23}}{\rightarrow}}\ = 108.6\ g\ (molar\ mass)$
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