Q. In the equation, $H_{2}S + 2{HNO}_{3} \rightarrow 2H_{2}O + 2{NO}_{2} + S$ The equivalent weight of hydrogen sulphide is
A) 18
B) 68
C) 34
D) 17
Explanation
(d)
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Hence, the equivalent weight of
$H_{2}S = \frac{molecular\ weight}{change\ in\ oxidation\ number} = \frac{34}{2} = 17$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.