Q. The number of hydrogen atoms present in 25.6 g of sucrose($C_{12}H_{22}O_{11}$) which has a molar mass of 342.3 g is
A) $22 \times 10^{23}$
B) $9.91 \times 10^{23}$
C) $11 \times 10^{23}$
D) $44 \times 10^{23}$ H atoms
Explanation
(b)
Mole of sucrose = $\frac{mass\ of\ sucrose\ (in\ gram)}{molecular\ weight\ of\ sucrose}$
= $\frac{\ 25.6\ }{342.3}$=0.0747882
Formula of sucrose =$C_{12}H_{22}O_{11}$
Number of H atoms in 1 mole of sucrose
= $22 \times 6.023 \times 10^{23}$
Number of H atoms in 0.0747882 mole of sucrose
= $22 \times 6.023 \times 10^{23} \times 0.074788$
= $9.9 \times 10^{23}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.