Q. 3 g of an oxide of a metal is converted to chloride completely and it yielded 5 g of chloride. The equivalent weight of the metal is
A) 33.25
B) 3.325
C) 12
D) 20
Explanation
(a)
$\frac{Wt.of\ metal\ oxide}{Wt.of\ metal\ chloride}$
$= \frac{Eq.wt.of\ metal + Eq.wt.of\ oxide}{Eq.wt.of\ metal + Eq.wt.of\ chloride}$
$\frac{3}{5} = \frac{E + 8}{E + 35.5}$
$E = 33.25$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.