In the following reaction, $MnO_{2} + 4HCL \longrightarrow MnCl_{2} + 2H_{2}O + Cl_{2}$ $2\ mol\ MnO_{2}$ reacts with 4 $mol\$of $HCl$ to form 11.2 $L\ Cl_{2}a$t STP. Thus, per cent yield of $Cl_{2}$ is

Question

Dr. Abubacker · Accepted Answer

(b)
$MnO_{2} + 4HCl \longrightarrow MnCl_{2} + 2H_{2}O + cl_{2}$
2 mol 4 mol 1 mol
4 mol 22.4 L
But the yield is 11.2.
$	herefore\ \ \ \ \%$ yield $= \frac{11.2}{22.4} 	imes 100 = 50\%$

Q. In the following reaction, $MnO_{2} + 4HCL \longrightarrow MnCl_{2} + 2H_{2}O + Cl_{2}$ $2\ mol\ MnO_{2}$ reacts with 4 $mol\$of $HCl$ to form 11.2 $L\ Cl_{2}a$t STP. Thus, per cent yield of $Cl_{2}$ is

Explanation

Reviewed by Dr. Abubacker

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