In the disproportionation reaction $3{HClO}_{3} \rightarrow {HClO}_{4} + {Cl}_{2} + 2O_{2} + H_{2}O,$ the equivalent mass of the oxidising agent is (molar mass of ${HClO}_{3} = 84.45$)

Question

Dr. Abubacker · Accepted Answer

(a)
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Equivalent mass of $HClO_{3} = \frac{molar\ mass}{change\ in\ oxidation\ no.}$
$= \frac{84.45}{5} = 16.89$
(When it acts as an oxidising agent)

Q. In the disproportionation reaction $3{HClO}_{3} \rightarrow {HClO}_{4} + {Cl}_{2} + 2O_{2} + H_{2}O,$ the equivalent mass of the oxidising agent is (molar mass of ${HClO}_{3} = 84.45$)

Explanation

Reviewed by Dr. Abubacker

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