(d) $2C_{2}H_{2} + 5O_{2} \rightarrow 4CO_{2} + 2H_{2}O$ 2 cc 5 cc 100 cc 250 cc Hence, air will be needed $= \frac{100}{20} \times 250$ =$1250$ cc
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.