Q.
There are two isotopes of an element with atomic mass$z$. Heavier one has atomic mass $z + 2$ and lighter one has z$- 1$, the abundance of lighter one is
A) 66.6%
B) 69.7%
C) 6.67%
D) 33.3%
Explanation
(a)
Let the percent abundance of lighter isotope is $x$.
$\therefore$ Atomic mass, $z = \frac{x(z - 1) + (100 - x)(z + 2)}{z + 100 - x}$
$3x = 200$ or $x = 66.6\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.