Q. The empirical formula of a compound is${CH}_{2}$. One mole of this compound has a mass of 56 g. its molecular formula is
A) $C_{3}H_{6}$
B) $C_{4}H_{8}$
C) ${CH}_{2}$
D) $C_{2}H_{2}$
Explanation
(b)
Weight of empirical formula $CH_{2}$=14
Mass of 1 mole=molecular weight=56
$n = \frac{molecular\ weight}{empirical\ formula\ weight} = \frac{56}{14} = 4$
Molecular formula=$\left( CH_{2} \right)_{4}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = C_{4}H_{8}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.