Q. 1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is
A) 1.52
B) 0.995
C) 190
D) 9
Explanation
(d)
$\frac{E_{hydroxide}}{E_{metal} + E_{OH^{-}}} > \frac{E_{oxide}}{E_{metal} + E_{O}}$
$\frac{1.520}{E + 17} = \frac{0.995}{E + 8}$
or $E = 9$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.