Q. The equivalent weight of ${KIO}_{3}$ in the reaction, $2Cr(OH)_{3} + {OH}^{-} + {KIO}_{3} \rightarrow 2{CrO}_{4}^{2 -} + 5H_{2}O + KI$ is
A) Mol. wt.
B) Mol. wt./3
C) Mol. wt./6
D) Mol. wt./2
Explanation
(c)
$2Cr(OH)_{3} + {4OH}^{-} + {KIO}_{3} \rightarrow 2{CrO}_{4}^{2 -} + 5H_{2}O + KI$
Change in oxidation number of effective element (I) in
$KIO_{3} = ( + 5) - ( - 1) = 6$
Equivalent weight of oxidation=$\frac{mol.\ \ wt.}{6}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.