Q. How many moles of ${Al}_{2}\left( {SO}_{4} \right)_{3}$ would be in 50 g of the substance?

A) 0.083 mol
B) 0.952 mol
C) 0.481 mol
D) 0.140 mol
Explanation

(d)
$Moles = \frac{mass}{molecular\ mass}$
Given, mass of $Al_{2}\left( SO_{4} \right)_{3} = 50g$
Molecular mass of $Al_{2}\left( SO_{4} \right)_{3} = 342\ g$
$\therefore\ \ \ \ \ \ \ Moles\ of\ Al_{2}\left( SO_{4} \right)_{3} = \frac{50}{342} = 0.14$ mol

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.