(d)
$Moles = \frac{mass}{molecular\ mass}$
Given, mass of $Al_{2}\left( SO_{4} \right)_{3} = 50g$
Molecular mass of $Al_{2}\left( SO_{4} \right)_{3} = 342\ g$
$\therefore\ \ \ \ \ \ \ Moles\ of\ Al_{2}\left( SO_{4} \right)_{3} = \frac{50}{342} = 0.14$ mol