Q. In the following reaction, which choice has value twice that of the equivalent mass of the oxidizing agent? $SO_{2} + H_{2}O \longrightarrow 3S + 2H_{2}O$
A) 64
B) 32
C) 16
D) 48
Explanation
(b)
Eq. wt. of $SO_{2} = \frac{molar\ mass}{O.N.of\ S} = \frac{64}{4} = 16$
$\therefore$ Twice of this value = 32
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.