Q. The number of atoms in 4.25 g of ${NH}_{3}$ is approximately
A) $6 \times 10^{23}$
B) $2 \times 10^{23}$
C) $1.5 \times 10^{23}\$
D) $1 \times 10^{23}$
Explanation
(a)
Weight of $NH_{3} = 4.25$g
We know that number of atoms in 1 mole or 17 g of
$NH_{3} = 4 \times 6.023 \times 10^{23}$
$\therefore$ Number of atom in 4.25 g of
$NH_{3} = \frac{4 \times 6.023 \times 10^{23}}{17} \times 4.25$
$= 6.023 \times 10^{23}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.