Explanation

(d)
$\because$ 0.0833 mole of carbohydrate has hydrogen=1 g
$\therefore$ 1 mole of carbohydrate has hydrogen
$= \frac{1}{0.0833} = 12$ g
Given, empirical formula of carbohydrate $\left( CH_{2}O \right)$ has 2 g of hydrogen$.$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ n = \frac{12}{2} = 6$
$\therefore$ Molecular formula of carbohydrate is
$\left( CH_{2}O \right)_{n} = \left( CH_{2}O \right)_{6} = C_{6}H_{12}O_{6}$