Q. The equivalent weight of a solid element is found to be 9. If the specific heat of this element is $1.05\ {Jg}^{- 1}K^{- 1},$ then its atomic weight is
A) 17
B) 21
C) 25
D) 27
Explanation
(d)
By using
Valency of an element=$\frac{approximate\ weight}{equivalent\ weight}$
$= \frac{26.8/specific\ heat}{equivalent\ weight}$
$= \frac{26.8/1.05}{9} = 2.835 \cong 3$
Now, by using
Atomic weight=equivalent weight$\times$ valency
$9 \times 3 = 27$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.