Q. A compound contains 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound is
A) $N_{2}O$
B) ${NO}_{2}$
C) $N_{2}O_{4}$
D) $N_{2}O_{5}$
Explanation
(c)
[table] Element | % | % At. wt. | Ratio ; N
O | 30.5
69.5 | 30.5/14=2.18
69.5/16=4.34 | 1
2 [/table]
Empirical formula=$NO_{2}$
Empirical formula weight=46
$n = \frac{92}{46} = 2$
$\therefore$ Molecular formula=$\left( NO_{2} \right)_{2} = N_{2}O_{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.