(a)
In the given metal nitride, nitrogen present is 28% that means, the nitride contains 28 g nitrogen and 72 g metal.
Moles of metal $= \frac{72}{x}$
Moles of nitrogen $= \frac{28}{14} = 2$
$\Longrightarrow$ Molar ratio, $M:N = \frac{72}{x}:2 = 3:2$
$\frac{72}{x} = 3$
$\therefore x = 24$