Q. 100 g of ${CaCO}_{3}$ is treated with 1 L of 1 N HCI. What would be the weight of ${CO}_{2}$ liberated after the completion of the reaction?
A) 55 g
B) 11 g
C) 22 g
D) 33 g
Explanation
(c)
$CaCO_{3} + 2HCl\overset{\mathrm{\Delta}}{\rightarrow}CaCl_{2} + H_{2}O + CO_{2}$
100 g 2 $\times$ 36.5g 44 g
1 L of 1 N HCl means=36.5 g HCl
Here, HCl is limiting reagent. Therefore, it reacts with 50 g
$CaCO_{3}$ and produces 22 g $CO_{2}$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.