Q. If the ionisation potential for hydrogen atom is 13.6 eV, then the ionisation potential for $He^{+}$ion should be
A) 13.6 eV
B) 6.8 eV
C) 54.4 eV
D) 72.2 eV
Explanation
(c)
IP for $Fe^{+}$ ion =IP for H×$(Z)^{2}$
where, $Z =$atomic number
$\therefore IP = 13.6 \times (2)^{2}$
$\ \ \ \ \ \ \ \ \ = 13.6 \times 4 = 54.4\ eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.