For an electron in a hydrogen atom, the wave function $\Psi$ is proportional to $\exp^{- t/a_{0}}\ ,$ where $a_{0}$ is the Bohr’s radius. What is the ratio of the probability of finding the electron at the nucleus to the probability of finding it at $a_{0}?$

Question

Dr. Abubacker · Accepted Answer

(d)
Higher values of $\Psi^{2}$ means greater probability for finding electron and a zero value of${\ \Psi}^{2}$ means the probability for finding the electron is zero (at nucleus)

Q. For an electron in a hydrogen atom, the wave function $\Psi$ is proportional to $\exp^{- t/a_{0}}\ ,$ where $a_{0}$ is the Bohr’s radius. What is the ratio of the probability of finding the electron at the nucleus to the probability of finding it at $a_{0}?$

Explanation

Reviewed by Dr. Abubacker

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