(b) $e/m\ ratio\ for\ He^{2 +} = \frac{2}{4}$ $e/m\ ratio\ for\ H^{+} = \frac{1}{1}$ $e/m\ ratio\ for\ He^{+} = \frac{1}{4}$ $e/m\ ratio\ for\ D^{+} = \frac{1}{2}$ $\therefore$ The $e/m$ is highest for hydrogen.
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.