Q. Energy of H-atom in the ground state is -13.6 eV, hence energy in the second excited state is
A) $- 6.8\ eV$
B) $- 3.4\ eV$
C) $- 1.51eV$
D) $- 4.53\ eV$
Explanation
(c)
$E_{n} = - \frac{13.6}{n^{2}}eV$
For second excited state $n = 3$,
$E_{3} = - \frac{13.6}{9} = - 1.51eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.