The energy of an electron in first Bohr orbit of H-atom is $- 13.\ 6$ eV. The possible energy value of electron in the excited state of $Li^{2 +}$ is

Question

Dr. Abubacker · Accepted Answer

(c)
$E_{n} = \frac{E_{1}}{n^{2}} 	imes Z^{2}$
$= \frac{- 13.6}{4} 	imes 9 = - 30.6\ eV$
(for the excited state, $n = 2$ and for $Li^{2 +}$ion, $Z = 3$)

Q. The energy of an electron in first Bohr orbit of H-atom is $- 13.\ 6$ eV. The possible energy value of electron in the excited state of $Li^{2 +}$ is

Explanation

Reviewed by Dr. Abubacker

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