Q. The energy of a photon is $3 \times 10^{- 12}$ergs. What is its wavelength in nm? $(h = 6.62 \times 10^{- 27}ergs,\ c = 3 \times 10^{10}cm/s)$

A) 662
B) 1324
C) 66.2
D) 6.62
Explanation

(a)
$E = 3 \times 10^{- 12}ergs$
$\lambda = ?$
$h = 6.62 \times 10^{- 27}ergs$
$c = 3 \times 10^{10}cms^{- 1}$
$E = \frac{hc}{\lambda}$
$3 \times 10^{- 2} = \frac{6.62 \times 10^{- 27} \times 3 \times 10^{10}}{\lambda}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda = \frac{6.62 \times 10^{- 27} \times 3 \times 10^{10}}{3 \times 10^{- 12}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 6.62 \times 10^{- 5}cm$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 662 \times 10^{- 7}cm$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 662 \times 10^{- 9}m$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 662\ nm.$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.