Q. What is the minimum energy that photons must posses in order to produce photoelectric effect with platinum metal? The threshold frequency for platinum is 1.3$\times 10^{15}s^{- 1}$
A) $3.6 \times 10^{- 13}$erg
B) 8.2$\times 10^{- 13}$erg
C) 8.2$\times 10^{- 14}$erg
D) 8.6$\times 10^{- 12}$erg
Explanation
(d)
The threshold frequency ($v_{0}$) is the lowest frequency that photons may possess to produce the photoelectric effect. The energy corresponding to this frequency is the minimum energy ($E$)
$E = hv_{0}$
$= (6.625 \times 10^{- 27}$erg s) $(1.3 \times 10^{15} \times s^{- 1})$
$= 8.6 \times 10^{- 12}$ erg
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.