Q. The energy of second Bohr orbit of the hydrogen atom is $- 328\ kJ\ mol^{- 1}$ ; hence the energy of fourth Bohr orbit would be
A) $- 41\ kJ\ mol^{- 1}$
B) $- 1312\ kJ\ mol^{- 1}$
C) $- 164\ kJ\ mol^{- 1}$
D) $- 82\ kJ\ mol^{- 1}$
Explanation
(d)
The energy of second Bohr orbit of hydrogen atom $\left( E_{2} \right)\ is - 328\ kJ\ mol^{- 1}$ because
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E_{2} = - \frac{1312}{2^{2}}kJ\ mol^{- 1}$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ E_{n} = - \frac{1312}{n^{2}}kJ\ mol^{- 1}$
If $n = 4$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ E_{4} = - \frac{1312}{4^{2}}kJ\ mol^{- 1}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = - 82\ kJ\ mol^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.