Q. Four different sets of quantum numbers for 4 electrons are given below $e_{1} = 4,\ 0,\ 0, - \frac{1}{2}:e_{2} = 3,\ 1,\ 1, - \frac{1}{2}$ $e_{3} = 3,\ 2,\ 2, + \frac{1}{2}:e_{4} = 3,\ 0,\ 0, + \frac{1}{2}$ The order of energy of $e_{1},e_{2},e_{3}$ and $e_{4}$ is
A) $e_{1} > e_{2} > e_{3} > e_{4}$
B) $e_{4} > e_{3} > e_{2} > e_{1}$
C) $e_{3} > e_{1} > e_{2} > e_{4}$
D) $e_{2} > e_{3} > e_{4} > e_{1}$
Explanation
(c)
Higher the $(n + l)$, higher will be the energy. If $(n + l)$ is same for two electrons, the electron for which $n$ is larger, energy is higher
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.