Q. Uncertainty in position of a particle of 25 g in space is $10^{- 5}m$. Hence, uncertainty in velocity $\left( ms^{- 1} \right)$ is (Planck’s constant $h = 6.6 \times 10^{- 34}Js$)

A) $2.1 \times 10^{- 28}$
B) $2.1 \times 10^{- 34}$
C) $0.5 \times 10^{- 34}$
D) $5.0 \times 10^{- 24}$
Explanation

(a)
$\mathrm{\Delta}x.\mathrm{\Delta}v \geq \frac{h}{4\pi m}$
$\mathrm{\Delta}x \geq \frac{6.62 \times 10^{- 34}}{4 \times 3.14 \times 25 \times 10^{- 3} \times 10^{- 5}}$
$\ \ \ \ \ \ \ \ \ \ \ \ = 2.10 \times 10^{- 28}m$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.