Q. The orbital angular momentum of an electron in $3s$-orbital is
A) $\frac{1}{2}.\frac{h}{2\pi}$
B) $\frac{h}{2\pi}$
C) $\frac{1}{3}.\frac{h}{2\pi}$
D) Zero
Explanation
(d)
The orbital angular momentum
$= \frac{h}{2\pi}\sqrt{l(l + 1)}$
For 3$s$-electron, $l = 0$
∴ Orbital angular momentum
$= \frac{h}{2\pi}\sqrt{0(0 + 1)}$
$= 0(zero)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.