Q. Which of the following reaction led to the discovery of neutrons?
A) $\ _{6}C^{16} + \ \ _{1}p^{1} \rightarrow \ \ \ _{7}N^{14} + \ \ _{0}n^{1}$
B) $\ _{4}{Be}^{9} + \ \ _{2}{He}^{4} \rightarrow \ \ \ _{6}C^{12} + \ \ _{0}n^{1}$
C) $\ _{5}B^{11} + \ \ _{1}D^{2} \rightarrow \ \ \ _{6}C^{11} + \ \ _{0}n^{1}$
D) $\ _{4}{Be}^{8} + \ \ _{2}{He}^{4} \rightarrow \ \ \ _{6}C^{11} + \ \ _{0}n^{1}$
Explanation
The correct answer is Option B: $\ _{4}{Be}^{9} + \ \ _{2}{He}^{4} \rightarrow \ \ \ _{6}C^{12} + \ \ _{0}n^{1}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.