Q. The orbital angular momentum for an electron revolving in an orbit is given by $\sqrt{l(l + 1)}\frac{h}{2\pi}$. This momentum for an $s$-electron will be given by
A) $+ \frac{1}{2}.\frac{h}{2\pi}$
B) Zero
C) $\frac{h}{2\pi}$
D) $\sqrt{2}.\frac{h}{2\pi}$
Explanation
(b)
For $s$-electron,$\ l = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.