Q. The set of quantum numbers for the outermost electron for copper in its ground state is
A) $4,\ 1,\ 1,\ + \frac{1}{2}$
B) $3,\ 2,\ 2,\ + \frac{1}{2}$
C) $4,\ 0,\ 0,\ + \frac{1}{2}$
D) $4,\ 2,\ 2,\ + \frac{1}{2}$
Explanation
(c)
The electronic configuration of the Cu atom is
$\ _{29}Cu = \lbrack Ar\rbrack 3d^{10}4s^{1}$
Since, the outermost shell is 4$s$, thus outermost electron is in it.
$For\ 4s^{1},$
$n = 4,\ \ \ l = 0,\ \ \ m = 0,\ \ \ \ s = + \frac{1}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.