Q. Which one of the following is the set of correct quantum numbers of an electron in $3d$ orbital?
A) $n = 3,\ l = 0,\ m = 0,\ s = - 1/2$
B) $n = 2,\ l = 3,\ m = 0,\ s = + 1/2$
C) $n = 3,\ l = 1,\ m = 0,\ s = - 1/2$
D) $n = 3,\ l = 2,\ m = 1,\ s = + 1/2$
Explanation
(d)
For 3$d$-orbital,
$n = 3\$
For $d$-orbital, $l = 2$
and $m = - 2,\ - 1,\ 0,\ + 1, + 2$
$\ \ \ \ \ \ \ \ \ \ s = \pm \frac{1}{2}$
$\therefore$ The correct set for 3$d$-orbital is
$n = 3,\ l = 2,\ m = 1,\ s = + \frac{1}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.