Q. How many unpaired electrons are present in $Ni^{2 +}$ cation? (At. No. = 28)
A) 0
B) 2
C) 4
D) 6
Explanation
(b)
$\ _{28}Ni = 1s^{2},2s^{2},2p^{6},3s^{2},3p^{6},4s^{2},3d^{8}$
$Ni^{2 +} = 1s^{2},2s^{2},2p^{6},3s^{2},3p^{6},3d^{8}$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.