Q. The potential energy of an electron present in the ground state of $Li^{2 +}$ ion is

A) $+ \frac{3e^{2}}{4\pi\varepsilon_{0}r}$
B) $- \frac{3e^{\ }}{4\pi\varepsilon_{0}r}$
C) $- \frac{3e^{2}}{4\pi\varepsilon_{0}r}$
D) $- \frac{3e^{2}}{4\pi\varepsilon_{0}r^{2}}$
Explanation

The correct answer is Option C: $- \frac{3e^{2}}{4\pi\varepsilon_{0}r}$.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.