(b) Energy of $e^{-}$ in the $n$th orbit of atom$= \frac{- 13.6}{n^{2}}eV/atom$ Given, $n = 5$ $\therefore\ \ E_{5} = - \frac{13.6}{(5)^{2}} = - \frac{13.6}{25} = - 0.54\ eV/atom$
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