Q. An electron with values 4, 2,$\ - 2$ and +1/2 for the set of four quantum numbers $n,\ l,\ m_{l}and\ s$ respectively, belongs to
A) $4s$-orbital
B) $4p$-orbital
C) $4d$-orbital
D) $4f$-orbital
Explanation
(c)
$n = 4$(4th shell)
$l = 2$($d$-subshell)
$m_{1} = - 2(d_{xy}$ orbital$)$
$s = + \frac{1}{2}( \uparrow )$
Hence, electron belongs to 4d-orbital.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.