(b)
EC of Cr ($Z = 24$) is
[table] Outer configuration | $n$ | $l$ ; $1s^{2}$ | 1 | 0 ; $2s^{2}$ | 2 | 0 ; $2p^{6}$ | 2 | 1 ; $3s^{2}$ | 3 | 0 ; $3p^{6}$ | 3 | 1 ; $3d^{5}$ | 3 | 2 ; $4s^{1}$ | 4 | 0 [/table]
Thus, electrons with $l = 1,\$are $12$
With $l = 2$, are 5